What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1)? Oy-(-3) --4(x-1) O y-1--4[*-(-3)] 0 -1-y,--4-3-x;) O 3-y,--4(1-x)

Question

asked May 5, 2021 46.2k views

1 Answer

Bani · Answer 1 · 2021-05-11T21:47:42+0000

Answer:

Option B)
y - 1= -4 [x-(-3)]

Explanation:

Slope = m = -4

Point = (x1,y1) = (-3,1)

So, x1 = -3, y1 = 1

Putting it in the point slope equation:

=>
y-y1 = m(x-x1)

=>
y - 1= -4 [x-(-3)]