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When mapping the equipotentials on the plates with different electrode configurations you may find that some have significant areas with uniform distribution of the equipotential lines. If the distance between such lines is 0.5 cm, what is the electric field there (in units SI)

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User Anqit
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1 Answer

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Answer:

E = V/5 x10⁻³

Step-by-step explanation:

if the potential difference is V

then electric field E is given by

E = V/d

d = 0.5cm = 5 x 10⁻³m

E = V/5 x10⁻³