Question

Please help me out with these questions.

*Quadratic equations*

solve;

(i) (x+3)(x-4)=0

(ii) (2x-3)(x-1) =0​ ​

Answer 1

`\huge\boxed{(i)\ x=-3\ \vee\ x=4}\\\boxed{(ii)\ x=1.5\ \vee\ x=1}`

Explanation:

We have the product of two expressions. The product is equal to 0 if and only if one of the factors is equal to 0.

Therefore

`(i)\\(x+3)(x-4)=0\iff x+3=0\ \vee\ x-4=0\\\\\boxed{x=-3\ \vee\ x=4}\\\\(ii)\\(2x-3)(x-1)=0\iff2x-3=0\ \vee\ x-1=0\\\\\boxed{x=1.5\ \vee\ x=1}`