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Solve the following system of equations: 2x+3y-z=1 3x+y+2z=12 x+2y-3z=-5

Solve the following system of equations: 2x+3y-z=1 3x+y+2z=12 x+2y-3z=-5
asked 60.8k views
2 votes
Solve the following system of equations: 2x+3y-z=1 3x+y+2z=12
x+2y-3z=-5

asked
User Pojo
by
8.4k points

2 Answers

4 votes

Answer:

x=-3 y=19/7 z=7

Explanation:

answered
User Ryan Michela
by
8.8k points
5 votes
x=-3 y=19/7 z=7 i’m not sure but i think
answered
User Domon
by
7.9k points
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