Question

K has the equation 2y + 3x – 5 = 0

L is a line perpendicular to K
Find the gradient of L

:3

Answer 1

The gradient of Line L =
`(2)/(3)`

Explanation:

The equation for K is:

=> 2y+3x-5 = 0

Arranging it in the form of slope-intercept equation:

=>
`y = -(3)/(2) x+(5)/(2)`

Since, Line L is perpendicular to Line K, The gradient of it would be the negative reciprocal of this gradient and multiplying both gives the result of -1.

So,

The gradient of Line L =
`(2)/(3)`