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The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not all of the energy in the circuit is dissipated b…

The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not all of the energy in the circuit is dissipated b…
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The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not all of the energy in the circuit is dissipated by the coil. Because the emf source has internal resistance, energy is also dissipated by the battery as heat. Calculate the rate of dissipation of energy PbatPbatP_bat in the battery.

asked
User Giohji
by
6.8k points

1 Answer

4 votes

Answer:

P = I²r

Step-by-step explanation:

ε= IR + Ir

where r is the internal resistance

The energy delivered to the resistive coil is dissipated as heat at a rate equal to-example-1
answered
User Alexey Shiklomanov
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7.9k points
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