Question

The escape velocity at Mercury's surface can be represented by the function

f(r) = 7.2r, where f(n) is the escape velocity in meters per second and r is the
radius of Mercury in meters. Mercury's radius is approximately 2,430,000 meters.
What is the minimuṁ velocity needed at Mercury's surface to escape its gravity?
Round to the nearest hundred.

Answer 1

We just plug in 2,430,000 for r and when we do so we get:

f(r) = √7.2 * 2,430,000 = 1080 * √15 = 4,200.