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B^2 + 8b + 16 factoring polynomials with a leading coefficient

1 Answer

5 votes

Answer:

(b +4)²

Explanation:

Here, you recognize the constant as the square of half the coefficient of the linear term: 16 = (8/2)². This means the trinomial is a perfect square, so can be factored accordingly.

b² +8b +16 = (b +4)²

answered
User Kaushik Ghose
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