Question

Find the equation of a

parabola with focus (6,0)

and vertex at the origin. Show all steps and explain please

Answer 1

y^2=2/3x

Explanation:

Since the vertex is at the orgin and the focus is on the right side of the x axis,

the parabola will open right!

(h,k)

it would be a y^2=4px equation

6/4 = 2/3

Just always divde four by the focus

Answer 2

If your vertex is at the orgin you can't have a point on (6,0)

Explanation: