Question

What is the permeter of square ABCD?

Answer 1

24.3 units (3 s.f.)

Explanation:

Since a square has 4 equal sides,

perimeter of ABCD= 4(length of AB)

Distance between 2 points

=
`\sqrt{(y1 - y2)^(2) + (x1 - x2)^(2) }`

Length of AB

`= \sqrt{( { - 2 - 4)}^(2) + {(2 - 3)}^(2) } \\ = \sqrt{( - 6)^(2) + ( - 1)^(2) } \\ = √(37)`

perimeter of ABCD

`= 4 √(37) \\ = 24.3 \: units \: (3 \: s.f.)`