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Which function has real zeros at x = 3 and x = 7?

Of(x) = x2 + 4x - 21
Of(x) = x2 - 4x – 21
O f(x) = x2 – 10x + 21
Of(x) = x2 – 10x - 21

2 Answers

7 votes

Answer:

C. f(x) = x2 – 10x + 21

Explanation:

Just had this on a test

answered
User Kidsunbo
by
7.6k points
4 votes

Answer:

x² - 10x + 21

Explanation:

the 3rd one

(x-3)(x-7)=0

answered
User Artch
by
7.2k points

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