Question

Find the equation of a circle that has its center at (6,-4) and has a radius of 3.​

Answer 1

I think it’s 9 but not sure

Answer 2

( x-6) ^2 + ( y+4) ^2 = 9

Explanation:

The equation of a circle is given by

( x-h) ^2 + ( y-k) ^2 = r^2 where (h,k) is the center and r is the radius

( x-6) ^2 + ( y- -4) ^2 = 3^2

( x-6) ^2 + ( y+4) ^2 = 3^2

( x-6) ^2 + ( y+4) ^2 = 9