Question

For f(x) = 2x + 1 and g(x) = x^2- 7, find (f - g)(x). ?

Answer 1

(f-g)(x)=-x^(2)+2x+8

the solutions are:

x=4 or x=-2

Explanation:

(f-g)(x)=2x+1-(x^(2)-7)

(f-g)(x)=-x^(2)+2x+1+7

(f-g)(x)=-x^(2)+2x+8

does this help or should I solve for the zeros/solutions of this quadratic equation?

then:

-x^(2)+2x+8=0

-(x^(2)-2x-8)=0

x^(2)-2x-8=0

(x-4)(x+2)=0

x=4 or x=-2

Answer 2

The required answer is: -x^2+2x+8

Explanation:

We have been given the two function:

f(x)=2x+1

And g(x)=x^2-7

We have to find (f-g)(x):

(f-g)(x)=f(x)-g(x)

(2x+1)-(x^2-7)

2x+1-x^2+7

-x^2+2x+8

Hence, the required answer is: -x^2+2x+8