Question

Find the value of "y" log(4y+1)=log(y-7)-2log2​

Answer 1

y = -8/15

Explanation:

log (4y + 1) = log (y - 7) - 2log2

log (4y + 1) = log (y - 7) - log2² (power law)

log (4y + 1) = log [(y - 7)/4]

4y + 1 = (y - 7)/4 (remove log)

4(4y + 1) = y - 7

16y - y = -8

15y = -8

y = -8/15