Question

student conducted an experiment and find the density of an ICEBERGE. A students than recorded the following readings. Mass 425 25   g Volume 405 15   mL What experimental value should be quoted for the density of the ICEBERG? Compare your answer with the density of water, which is 3 1.00 10  kg . Show any calculations necessary to justify your answer

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The experimental value of density is
`\rho = 1.05*10^(3) \ kg/m^3 \pm 101 \ kg/m^3`

Comparing it with the value of density of water (
`1.0*10^(3) \ kg/m^3`) we can see that the density of ice is greater

Step-by-step explanation:

From the question we are told

The mass is
`M = (425 \pm 25) \ g =(0.425 \pm 0.025) \ kg`

The volume is
`V = (405 \pm 15 ) \ mL = (0.000405 \pm 1.5*10^(-5)) \ m^3`

The experimental value of density is mathematically evaluated as

`\rho = (M)/(V)`

`\rho = (0.425)/(0.000405)`

`\rho = 1.05 *10^(3) \ kg/m^3`

The possible error in this experimental value of density is mathematically evaluated as

`(\Delta \rho)/(\rho) = (\Delta M)/(M) +(\Delta V)/(V)`

substituting value

`(\Delta \rho)/(1.05*10^(3)) = (0.025)/(0.425) +(1.5*10^(-5))/(0.000405)`

`\Delta \rho = 101 \ kgm^(-3)`

Thus the experimental value of density is

`\rho = 1.05*10^(3) \ kg/m^3 \pm 101 \ kg/m^3`