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A 1,269 kg rocket is traveling at 413 m/s with 2,660 kg of fuel on board. If the rocket fuel travels at 1,614 m/s relative to the rocket, what is the rockets final velocity after it uses half of its fuel?

1 Answer

7 votes

Answer:

About 2104m/s

Step-by-step explanation:


F=ma \\\\F=(2660kg)/(2)\cdot 1614m/s=2,146,620N \\\\2,146,620N=1,269kg\cdot a \\\\a\approx 1691m/s \\\\v_f=v_o+at=413m/s+1691m/s=2104m/s

Hope this helps!

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User CyberMew
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