Question

Tal TI

Find the root(s) of f(x) = (x-6)2(x + 2)2
-6 with multiplicity 1
-6 with multiplicity 2
6 with multiplicity 1
6 with multiplicity 2
-2 with multiplicity 1
-2 with multiplicity 2
2 with multiplicity 1
2 with multiplicity 2
DONE​

Answer 1

Explanation:

6 with multiplicity 2 as you can see this term (x-6) at the power 2

-2 with multiplicity 2 as you can see this term (x+2) at the power 2

hope this helps

Answer 2

d. f.

a. d. f.

3 2 3 2

crosses touches crosses touches crosses

d.

d.

b. c. e. f.

The degree of the polynomial is 3. By the fundamental theorem of algebra, the function has three roots. Two roots are given, so there must be one root remaining. By the complex conjugate theorem, imaginary roots come in pairs. The final root must be real.

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