Question

Algebra applications: find the value of x and y ​

Answer 1

x = 14, y = 20

Explanation:

`(8x + 26) \degree + 3x \degree = 180 \degree..(straight \: line \: \angle s) \\ (11x + 26) \degree = 180 \degree \\ 11x + 26 = 180 \\ 11x = 180 - 26 \\ 11x = 154 \\ \\ x = (154)/(11) \\ \\ \huge \red { \boxed{x = 14}} \\ \\ (5y + 38) \degree = (8x + 26) \degree..(vertical \: \angle s) \\ 5y + 38 = 8 * 14 + 26 \\ 5y + 38 = 112 + 26 \\ 5y + 38 = 138 \\ 5y = 138 - 38 \\ 5y = 100 \\ \\ y = (100)/(5) \\ \\ \huge \purple{ \boxed{ y = 20}}`

Answer 2

`x = 14\\y = 20 \\`

Explanation:

Finding x:

8x + 3x + 26 = 180 (Angle on a straight line add up to 180°)

11x = 180-26

11x = 154

Dividing both sides by 11

x = 14

Finding y:

3x + 5y + 38 = 180 (Angle on a straight line add up to 180°)

3(14) + 5y + 38 = 180

42 + 38 + 5y = 180

80 + 5y = 180

5y = 180-80

5y = 100

Dividing both sides by 5

y = 20