Question

Calculate the number of grams of sodium in 8.4g of NaC7H5O2 (sodium benzoate) express your answer using two significant figures.

PLEASE HELP!

Answer 1

1.3g of Na

Step-by-step explanation:

We'll begin by calculating the molar mass of sodium benzoate, NaC7H5O2. This is shown below:

Molar Mass of NaC7H5O2 = 23 + (12x7) + (5x1) + (17x2)

= 23 + 84 + 5 + 32

= 144g/mol

Now, we can obtain the mass of sodium, Na present in 8.4g of sodium benzoate, NaC7H5O2 as follow:

There are 23g of Na in 144g of NaC7H5O2.

Therefore, the mass of Na in 8.4g of NaC7H5O2 is given by:

23/144 x 8.4 = 1.3g.

Therefore, 1.3g of Na is present in 8.4g of sodium benzoate, NaC7H5O2.