asked 50.6k views
5 votes
I'M BEING TIMED HELP

The acceleration due to gravity is the constant of variation. What is the acceleration due to gravity of a falling object?

I'M BEING TIMED HELP The acceleration due to gravity is the constant of variation-example-1

2 Answers

4 votes

The acceleration due to gravity is 9.8 m/s^2.

answered
User Yerke
by
8.8k points
5 votes

Answer:

acceleration = 9.8 m/s^2

Explanation:

The problem expects the user to do the rate of change between any two pairs of (time, velocity) from the table, and see that they all render the same value. Notice as well that the rate of change of a difference in velocities divided a difference in time, will render units of acceleration (in this case
(m)/(s^2)

Let's use for example (0 s ,0 m/s) and the following point: (1 s, 9.8 m/s)

the rate of change is:
acceleration= (9.8-0)/(1-0) (m)/(s^2) =9.8 \, (m)/(s^2)

In fact you can use any two pairs of the table, and will get the same result.

So this is the acceleration is
9.8 \, (m)/(s^2)

answered
User Atomikpanda
by
8.0k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.