Question

A 0.4 kg rock is dropped through a 6m height. Find its speed as it hits the ground. What is its speed at half way down?

Answer 1

83.1557575 M/s

Step-by-step explanation:

V²=u²+2as

v=
`\sqrt{u ^(2) { + 2as}^( ) }`

u is initial velocity =0

here a =g

`v = √(2gs)`

v=

`√(2 * 9.8 * 6)`

v= 83.1557575 M/s