Question

Please answer this correctly

Answer 1

`\boxed{Perimeter \: of \: semicircle = 61.68 \: feet}`

Given:

`\sf Area \: of \: semicircle = 226.08 \: square \: feet`

To find:

Perimeter of semicircle

Explanation:

Let 'r' be the radius of circle

`\sf \implies Area \: of \: semicircle = \frac{ \pi {r}^(2) }{2} \\ \\ \sf \implies 226 .08 = \frac{\pi {r}^(2) }{2} \\ \\ \sf \implies \frac{\pi {r}^(2) }{2} = 226.08 \\ \\ \sf \implies \pi {r}^(2) = 2 * 226.08 \\ \\ \sf \implies \pi {r}^(2) = 452.16 \\ \\ \sf \implies 3.14 * {r}^(2) = 452.16 \\ \\ \sf \implies {r}^(2) = (452.16)/(3.14) \\ \\ \sf \implies {r}^(2) = 144 \\ \\ \sf \implies {r}^(2) = {12}^(2) \\ \\ \sf \implies \sqrt{ {r}^(2) } = \sqrt{ {12}^(2) } \\ \\ \sf \implies r = 2 \: feet`

So,

`\sf Perimeter \: of \: semicircle = \pi r + 2r \\ \\ \sf =( 3.14 * 12) +( 2 * 12)\\ \\ \sf = 37.68 + 24 \\ \\ \sf = 61.68 \:ft`