Question

Question in attachment

Answer 1

a₁ = 3

Explanation:

The sum to n terms of a geometric sequence is

`S_(n)` =
`(a_(1)(r^(n)-1) )/(r-1)`

where a₁ is the first term and r the common ratio

Here
`S_(6)` = 189 and r = 2, thus

`(a_(1)(2^(6)-1) )/(2-1)` = 189, that is

a₁( 64 - 1) = 189

63a₁ = 189 ( divide both sides by 63 )

a₁ = 3