Question

Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2). y = - 1/3x + 1 y = -3 x -1 y = 9 x -1 y = 1/3x -1

Answer 1

y = - 1/3 x + 1

Explanation:

(6, -1) and (-3, 2)

Slope = (y2 - y1)/(x2 - x1) = (2 - (-1))/(-3-6) = 3/(-9) = - (1/3)

y-int form is y = ma +b

y = - 1/3 x +b

(-3, 2)

2 = (- 1/3)*(- 3)+ b

2 = 1 + b

b = 1

y = - 1/3 x + 1