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If |x−2|=p, where x<2, then x−p = (A) −2 (B) 2 (C) 2−2p (D) 2p−2 (E) |2p−2|

If |x−2|=p, where x<2, then x−p = (A) −2 (B) 2 (C) 2−2p (D) 2p−2 (E) |2p−2|
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If |x−2|=p, where x<2, then x−p = (A) −2 (B) 2 (C) 2−2p (D) 2p−2 (E) |2p−2|

asked
User Rudker
by
7.2k points

1 Answer

4 votes

Answer:

A

Explanation:

is the answer because x-x = 0

since -2 is left that's the answer!

answered
User Hiroyo
by
8.8k points
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