Question

PLEASE HELP ME :( Solve N = 3pg^2 - 2pv for v.

Answer 1

v =
`(3pg^2-N)/(2p)`

Explanation:

Given

N = 3pg² - 2pv ( isolate term with v by subtracting 3pg² from both sides )

N - 3pg² = - 2pv ( multiply through by - 1 to clear the negatives )

3pg² - N = 2pv ( divide both sides by 2p )

`(3pg^2-N)/(2p)` = v