Question

An object that is 0.5 m above the ground has the same amount of potential energy as a spring that is stretched 0.5 m. Each distance is then doubled.

How will the potential energies of the object and the spring compare after the distances are doubled?

Answer 1

Answer: The correct answer is The aplastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.

Explanation: The formula for Gravitational potential energy is= mgh where

m= mass

g= 9.8

h= height

On the other hand the formula for elastic potential energy is (1/2)KX^2

Where K is the spring. By changing the values of H and X, we will see elastic potential energy will remain more.

Answer 2

the answer is C

Step-by-step explanation:

took the test one edge