asked 191k views
3 votes
Write 6(x - 5)^4+ 4(x - 5)^2 + 6 = 0 in the form of a quadratic by using substitution

2 Answers

1 vote

Answer:

6u^2+4u+6=0, where u=(x-5)^2

or for short B

Explanation:

2020edge

answered
User George Cscnt
by
8.3k points
6 votes

Answer:

3m^2+2m+3=0

Explanation:

6(x - 5)^4+ 4(x - 5)^2 + 6 = 0

  • (x-5)^2= m

6m^2+4m+6=0

or

3m^2+2m+3=0

answered
User Ronaldo Cano
by
8.7k points

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