Question

The angle of deperession of aPt A, as measured form the top of

abuilding 30m tall is 450, how far is A from the basc of the
building?
A. 97m B. 30m C. 45m D. 32m

Answer 1

Answer:B

Explanation:

Given

Height of building
`h=30\ m`

Angle of depression
`\theta =45^(\circ)`

Suppose distance of Point A from base of building be
`x`

From diagram we can write

`\Rightarrow \tan \theta =(h)/(x)`

`\Rightarrow \tan (45^(\circ))=(30)/(x)`

`\Rightarrow 1=(30)/(x)`

`\Rightarrow x=30\ m`

So, point A is
`30\ m` from base of building