Question

A certain car traveling 34.0 mph skids to a stop in 29 meters from the point where the brakes were applied. In approximately what distance would the car stop had it been going 105.4 mph?

Answer 1

279 m

Explanation:

Work by friction = change in kinetic energy

Fd = ½ mv²

d ∝ v²

d / 29 m = (105.4 mph)² / (34.0 mph)²

d = 279 m