Question

How many moles of phosphoric acid are required to neutralize 7.2 mol of potassium hydroxide?

Answer 1

2.4 Moles of Phosphoric acid are required to neutralize 7.2 moles of potassium hydroxide

Step-by-step explanation:

Phosphoric acid = Formula: H3PO4

Potassium hydroxide = Formula: KOH

H3PO4 + 3KOH = K3PO4 + 3H2O

Ratio 1:3

7.2 mol Potassium hydroxide = Formula: KOH

7.2/3 = 2.4 Mol Phosphoric acid = Formula: H3PO4