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If 96 as a product of its prime factors is 2x2x2x2x2x3, find the greatest common divisor of 72 and 96

If 96 as a product of its prime factors is 2x2x2x2x2x3, find the greatest common divisor of 72 and 96
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If 96 as a product of its prime factors is 2x2x2x2x2x3, find the greatest common divisor of 72 and 96

asked
User Cryptjar
by
7.9k points

1 Answer

5 votes

Answer:

24

Explanation:

72=2*2*2*3*3

96=2*2*2*2*2*3

Hcf=2*2*2*3=24#

answered
User Tomikiss
by
8.7k points
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