Question

Make subject of the formula ​

Answer 1

Answer:This is what i could solve hope it helps :)

Number17

`H = (m(v^2-u^2)/(2gx) \\Cross - multiply\\2Hgx = m (v^2-u^2)\\2Hgx = mv^2-mu^2\\(2Hgx+mu^2)/(m) = (mv^2)/(m) \\Divide -both -sides-of-the-equation-by-m\\v^2 = (2Hgx+mu^2)/(m)\\Square - root-both -sides -to -eliminate the square\\v =\sqrt{(2Hgx+mu^2)/(m)}`

Explanation:

Number 19

`T =2\pi \sqrt{(1)/(MH)}\\Divide - both - sides-of-the-equation-by 2\pi\\\frac{2\pi \sqrt{(1)/(MH)}}{2\pi }=(T)/(2\pi )\\\sqrt{(1)/(MH)}=(T)/(2\pi )\\SQUARE-BOTH -SIDES\\\left(\sqrt{(1)/(MH)}\right)^2=\left((T)/(2\pi )\right)^2\\(1)/(MH)=(T^2)/(4\pi ^2)\\CROSS-MULTIPLY\\MHT^2={4\pi ^2\\\\DIVIDE BOTH SIDES OF THE EQUATION BY HT^2\\M=(4\pi ^2)/(HT^2)`

Number 20 &21

`A =(1)/(2) m(v^2-u^2)\\Divide both sides by (1)/(2) m\\((1)/(2)m\left(v^2-u^2\right))/((1)/(2)m)=(A)/((1)/(2)m)\\2Am = v^2-u^2\\Move- v^2- to- the -other -side- to- isolate- u\\\\u^2 = 2Am-v^2\\Square-root-both-sides-to -eliminate-the-square-on-u.\\u = √(2Am-v^2)`