Question

A number is selected from the set (1, 2, 3, 5, 15, 21, 29, 38, 500). If equal elemental probabilities are assigned, what is

the probability that the number chosen is either less than 29 or odd?

Answer 1

`(7)/(9)` OR 77.78%

Explanation:

So, we first need to find out how many numbers fit the "less than 29 or odd" group.

This would be: 1, 2, 3, 5, 15, 21, and 29, which is a total of 7 numbers.

Next, we figure out the total amount of numbers in the population.

This would be: 1, 2, 3, 5, 15, 21, 29, 38, and 500, which is a total of 9 numbers.

Finally, we put the first number (7) over the total (9) =
`(7)/(9)`

`(7)/(9)` is now able to be written in a percentage, if you need.

The probability is
`(7)/(9)` OR 77.78%