Question

A dance club hires two different DJ’s to

play music on a Friday night. The hip hop
DJ charges $100 per hour, while the rap DJ
charges $50 per hour. The club can spend
a maximum of $800, and they want both
types of music played.
Let “x” represent the number of hours of
hip hop and let “y” represent the number
of hours of rap.

Answer 1

The expression is 100x + 50y ≤ 800.

Explanation:

The hip hop DJ charge for $100 per hour. Let x be number of hours of hip hop :

`hip \: hop = 100 * x`

`hip \: hop = 100x`

For rap DJ, the charge is $50 per hour. Let y be the number of hours of rap :

`rap = 50 * y`

`rap = 50y`

Given that both DJs spend a maximum of $800. So the final expression is :

`100x + 50y \leqslant 800`