Question

A biker passes a lamppost at the crest of a hill at +4.5 m/s. She accelerates down the hill at a

constant rate of +0.40 m/s² for 12 s. How far does she move down the hill during this time?

Answer 1

82.8 m

Step-by-step explanation:

`d = v_(0)t + (at^_2)/(2)\\\\d = 4.5 m/s*12s +(0.40 m/s^(2)*(12s)^(2))/(2) = 82.8 m`