Question

Whatt is the equation of the line that passes through the points (-3,-3) and (3,1)

Answer 1

`m=(y_2 -y_1)/(x_2 -x_1)`

And replacing we got:

`m=(1-(-3))/(3-(-3))= (4)/(6)=(2)/(3)`

And we can use one of the points in order to find the intercept like this:

`-3= (2)/(3) (-3) +b`

`b =-3 +2=-1`

And the equation would be given by:

`y= (2)/(3)x -1`

Explanation:

We want an equation given by:

`y=mx+b`

where m i the slope and b the intercept

We have the following two points given:

`(x_1 = -3, y_1 =-3), (x_2=3, y_2 =1)`

We can find the slope with this formula:

`m=(y_2 -y_1)/(x_2 -x_1)`

And replacing we got:

`m=(1-(-3))/(3-(-3))= (4)/(6)=(2)/(3)`

And we can use one of the points in order to find the intercept like this:

`-3= (2)/(3) (-3) +b`

`b =-3 +2=-1`

And the equation would be given by:

`y= (2)/(3)x -1`