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1 vote
How many moles are in 27.10 g of potassium (K)?

asked
User Newaj
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1 Answer

2 votes

Answer: 0.701 mol K

Step-by-step explanation:

To find the number of moles in 21.10 g of K, we would need to know the molar mass of K.

K=30.098 g/mol

We would divide 27.10 moles by the molar mass to find how many moles of K are in 27.10 g.


21.10g*(1mol)/(30.098g) =0.701 mol

answered
User Stefita
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