Question

What volume will be occupied by 11.7 g of Helium in a balloon at an altitude of 10.0 km if the air pressure is 0.262 atm and the temperature is -50.0 °C?

Answer 1

Answer: 204 L

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 0.262 atm

V = Volume of gas = ?

n = number of moles =
`\frac{\text {given mass}}{\text {molar mass}}=(11.7g)/(4g/mol)=2.92`

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`-50^0C=(273+(-50))K=223K`

`V=(nRT)/(P)`

`V=(2.92* 0.0820 L atm/K mol* 223K)/(0.262atm)=204L`

Thus volume occupied by 11.7 g of Helium in a balloon is 204L