Question

What is the solution of log(3x+4)^125 = 3? (3x+4) is the base. 125 is the argument.

x=1/3
x=1
x=7/3
x=4

Answer 1

x = 1/3

Explanation:

`= > log_((3x + 4))125 = 3`

`= > {(3x + 4)}^(3) = 125 \: ( \because \: log_(a)b = x = > {a}^(x) = b)`

`= > 3x + 4 = \sqrt[3]{125} = 5`

`= > 3x = 5 - 4 = 1`

`\therefore \: \: x = (1)/(3)`

Hope you've understood the solution.