You have nitrogen gas (N2) at a pressure of 0.5 atm, a volume of 25000 mL, and a temperature of 300 K, how many grams of nitrogen are present?

Question

asked Dec 5, 2021 80.1k views

1 Answer

Farid Khafizov · Answer 1 · 2021-12-10T14:33:22+0000

Answer:

About 7.109g

Step-by-step explanation:

25000mL is the same as 25 liters.

$PV=nRT \\\\0.5 (25)=n (0.0821) (300) \\\\n\approx 0.508$

Multiplying this by the molar mass of nitrogen, you get about 7.109 grams of nitrogen. Hope this helps!