Question

describe the slope of the graph from 1 sec to 5.3 sec ( is the slope positive, negative, zero or non existent)

Answer 1

`m =(y_2 -y_1)/(x_2 -x_1)`

Where x for this case represent the time and y the height waist off ground.

We have one point that can be extracted from the graph on this case:

`x_1 = 1, y_1= 3`

Bout for the other point we have:

`x_2 = 5.3 , y_2 = 9.6`

Is important to notice that 9.6 is an estimation since we don't have the scale to identify the real value. so then if we replace we got:

`m =(9.6-3)/(5.3-1)= 1.535`

And for this case we can conclude that this slope is positive and around 1.5 and 1.6. And that means if we increase the time in one unit then the height off waist off ground would increae about 1.5 to 1.6 ft

Explanation:

In order to calculate the slope we need to use the following formula:

`m =(y_2 -y_1)/(x_2 -x_1)`

Where x for this case represent the time and y the height waist off ground.

We have one point that can be extracted from the graph on this case:

`x_1 = 1, y_1= 3`

Bout for the other point we have:

`x_2 = 5.3 , y_2 = 9.6`

Is important to notice that 9.6 is an estimation since we don't have the scale to identify the real value. so then if we replace we got:

`m =(9.6-3)/(5.3-1)= 1.535`

And for this case we can conclude that this slope is positive and around 1.5 and 1.6. And that means if we increase the time in one unit then the height off waist off ground would increae about 1.5 to 1.6 ft