Question

For each sequence, find the first 4 terms of a sequence:

a) n²+3
b) 2n²

Answer 1

a) 4, 7, 12, 19

b) 2, 8, 18, 32

Explanation:

In order to find the first 4 terms, you have to substitute 1 to 4 into n for both expressions :

`a) {n}^(2) + 3`

`1st \: term \\ {1}^(2) + 3 = 4`

`2nd \: term \\ {2}^(2) + 3 = 7`

`3rd \: term \\ {3}^(2) + 3 = 12`

`4th \: term \\ {4}^(2) + 3 = 19`

`b)2 {n}^(2)`

`1st \: term \\ 2( {1}^(2) ) = 2`

`2nd \: term \\ 2( {2}^(2) ) = 2(4) = 8`

`3rd \: term \\ 2( {3}^(2) ) = 2(9) = 18`

`4th \: term \\ 2( {4}^(2) ) = 2(16) = 32`

Answer 2

a) 4, 7, 12, 19

b) 2, 8, 18, 32

Explanation:

Sequence is just number line sir, so to begin with you get n=1, then n=2, then n=3, then n=4, these are the first 4 terms