Question

100. mL of a gas are obtained from a reaction at 300.⁰C. What volume will the gas occupy at 100.⁰C?

Answer 1

The new volume is 65.1 mL.

Step-by-step explanation:

We have,

Initial volume of the gas is 100 mL

Initial temperature is 300 degrees Celsius

It is required to find the volume the gas will occupy at 100 degrees Celsius. Charles law gives the relation between volume and temperature such that,

`V\propto T`

So,

`(V_1)/(V_2)=(T_1)/(T_2)`

V₂ is new volume

`V_2=(V_1T_2)/(T_1)`

V₁ = 100 mL

T₁ = 300 C = 573.15 K

T₂ = 100 C = 373.15 K

Plugging into formula we get :

`V_2=(100* 373.15)/(573.15)\\\\V_2=65.1\ mL`

So, the new volume is 65.1 mL.