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How do you complete the square of h(x)= x^2 + 6x + 7

How do you complete the square of h(x)= x^2 + 6x + 7
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1 vote
How do you complete the square of h(x)= x^2 + 6x + 7

asked
User Rekcs
by
8.4k points

1 Answer

1 vote

Answer:


(x + 3)^(2) - 2

Explanation:


h(x)= x^2 + 6x + 7 \\ = x^2 + 2.3.x + {3}^(2) - {3}^(2) + 7 \\ = (x + 3)^(2) - 9 + 7 \\ \purple { \bold{h(x)= (x + 3)^(2) - 2 }}

answered
User Cort Ammon
by
8.2k points
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