Question

Convert the following complex number into its polar representation:

-40
O A. 4(6052isang
37
B. 2(cos(+ isin)
C. 16(COST* isin x)
O D. -4(cose i sin

Answer 1

The correct option is B. 3√2(cos(135°) + i·sin(135°))

Explanation:

The complex number is given as : 3 - 3i

Now, comparing this with the standard for : a + bi

⇒ a = 3 and b = -3

Now, r = √a² + b²

⇒ r = √18

⇒ r = 3√2

Now, The polar form is represented by :

z = r(cosθ + i·sinθ)

⇒ z = 3√2(cos 135° + i·sin 135°)

Therefore, the correct option is B. 3√2(cos(135°) + i·sin(135°))

Explanation: