Two dogs play tug of war with a rope toy that has a mass of 0.50 kg. If one dog pulls on the toy with a force of 140.0 N, and the other dog pulls in the opposite direction with …

Question

asked Jan 8, 2021 63.6k views

1 Answer

Nellie Danielyan · Answer 1 · 2021-01-14T13:54:39+0000

Answer:
$4\ m/s^2$

Step-by-step explanation:

Given

mass of toy
$m=0.5\ kg$

Force by first dog
$F_1=140\ N$

Force by second dog is
$F_2=138\ N$

Net force on the dog is

F_(net)=F_1-F_2=140-138

$F_(net)=2\ N$

and
F_(net)=ma

a=(F_(net))/(m)

a=(2)/(0.5)

$a=4\ m/s^2$

So, horizontal acceleration of the toy is
$4\ m/s^2$