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Match the width with the go given area.

Match the width with the go given area.-example-1
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User Tholu
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Hello!

Answer:


\boxed{ \bf 1.~l~=~9.25~cm;~A~=~55.5~cm^2~matches~with~the~last~option~w~=~6~cm.}


\boxed{ \bf 2.~l~=~7.5~cm;~A~=~48.75~cm^2~matches~with~the~second~option~w~=~6.5~cm.}


\boxed{ \bf 3.~l~=~5~cm;~A~=~44~cm^2~matches~with~the~third~option~w~=~8.8~cm.}


\boxed{ \bf 4.~l~=~5~cm;~A~=~31.25~cm^2~matches~with~the~first~option~w~=~6.25~cm.}

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Step-by-step explanation:

We already know that the formula for area of a rectangle is A = l × w.

Notice how the width and the length are being multiplied to find the area.

Well, to find the width, we must do the opposite of multiplication, which is division.

Since we already have the length, all we have to do is divide the area by the length for each of the questions.

1:

A = l × w

55.5 = 9.25 × w


(55.5)/(9.25) = 6

2:

A = l × w

48.75 = 7.5 × w


(48.75)/(7.5) = 6.5

3:

A = l × w

44 = 5 × w


(44)/(5) = 8.8

4:

A = l × w

31.25 = 5 × w


(31.25)/(5) = 6.25

answered
User Nkrkv
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8.5k points

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