Question

Given the equation (x - 13) ^ 2 + y ^ 2 = 64 identify the center and radius

Answer 1

radius is 8; center is at (13, 0).

Explanation:

Compare the given (x - 13) ^ 2 + y ^ 2 = 64 to:

(x - h)^2 + (y - k)^2 = r^2. (h, k) represents the center

and r the radius.

Since 64 = r^2, r = the radius = 8 units = r

We also see that h = 13 and k = 0.

Thus, the center of the given circle is (13, 0).