Question

Jose drove 300 miles on his vacation. He drove an average of 1.5 times faster on the second 150 miles of his trop than he did on the first 150 miles of his trip. How much time did he spend driving? Let x = his speed on the first half of the trip.

Answer 1

Answer:
`t=(250)/(x)`

Explanation:

Given

Jose drives
`300\ miles`

In first 150 miles he 1.5 times faster than the second half

Let
`x (miles/hr)` be the speed on the second half so

in first half speed is
`1.5x`

time taken in first half
`t_1=\frac{\text{Distance}}{\text{speed}}`

`\Rightarrow t_1=(150)/(1.5x)`

For second half

`\Rightarrow t_2=(150)/(x)`

Total time
`=t_1+t_2`

`t=(150)/(1.5x)+(150)/(x)`

`t=(250)/(x)\ hr`